-425x^2+45500x-400000=0

Solution for -425x^2+45500x-400000=0 equation:

-425x^2+45500x-400000=0

a = -425; b = 45500; c = -400000;
Δ = b2-4ac
Δ = 455002-4·(-425)·(-400000)
Δ = 1390250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1390250000}=\sqrt{250000*5561}=\sqrt{250000}*\sqrt{5561}=500\sqrt{5561}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45500)-500\sqrt{5561}}{2*-425}=\frac{-45500-500\sqrt{5561}}{-850}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45500)+500\sqrt{5561}}{2*-425}=\frac{-45500+500\sqrt{5561}}{-850}
$